pipex

Permalink Failed to load latest commit information. A simple script to test Pipex, a 42 project to learn fork, redirection, and pipe in C programming. Clone the repository in your Pipex directory, go in the tester directory, and run tester.sh. Warning: Linux system compatibility (macos false negative)!

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I believe the issue here is that your waiting and closing inside the same loop that's creating children. On the first iteration, the child will exec (which will destroy the child program, overwriting it with your first command) and then the parent closes all of its file descriptors and waits for the child to finish before it iterates on to creating the next child.

I'm trying to make a program that executes the following commands connecting the output of one to the input of the next using pipes and taking two arguments DIR (directory) and ARG (filetype, examp...

Does your script start with the hashbang line? I think that's a must, something like: For example, see the following C program: #include #include char *argv[10] = { "./qq.sh", "file1", NULL }; int main (void) { int rc = execve (argv[0], argv, NULL); printf ("rc = %d\n", rc); return 0; } When this is compiled and run with the following qq.sh file, it outputs rc = -1: when you change the file to: #!/bin/bash echo $1 it outputs: as expected.

일단 exec 함수에 대해 설명하자면 string exec ( string $command [, array &$output [, int &$return_var ]] ) 위와 같은 파라미터를 가지고 있고, 보통 리눅스상에서 명령어를 수행할 때 쓴다. 보통 $var = exec("ls -l /var")처럼 단일로 쓰일때는 반환된 값의 마지막 줄만 가져오기 때문에 $var에는 ls 명령어로 쓰인 내용의 마지막 줄만 가져 온다.